We still have three separate grounds. At the input jack ground I connect a single wire from the power supply ground. I like to use something with low impedance to do this, often silver wire. Also at the input jack ground I attach a single wire from the active circuitry ground also with a low impedance wire. In this arrangement, neither ground is contaminated with voltages from the other. An obvious question now is that if you provide power to something in the active portion of the circuit, will not the current end up in the signal ground. The short answer is yes. It is also unavoidable and generally rather small in magnitude and normally does not cause problems. An exception is in power output stages. The large amount of current involved can cause noise in the signal ground so I ground them separately to the input jack ground. Could you run separate ground wires from each place in the active circuitry that puts current into the ground path? Certainly, and it would be a type of "star" ground system. I find generally it unnecessary. I can achieve signal to noise ratios of -90 dBV in high gain circuits without going to that method.
Unlike the Class A amplifier mode of operation above that uses a single transistor for its output power stage, the Class B Amplifier uses two complimentary transistors (either an NPN and a PNP or a NMOS and a PMOS) for each half of the output waveform. One transistor conducts for one-half of the signal waveform while the other conducts for the other or opposite half of the signal waveform. This means that each transistor spends half of its time in the active region and half its time in the cut-off region thereby amplifying only 50% of the input signal.
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